The Bits class¶
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class
bitstring.Bits([auto, length, offset, **kwargs])¶ Creates a new bitstring. You must specify either no initialiser, just an
autovalue, or one of the keyword argumentsbytes,bin,hex,oct,uint,int,uintbe,intbe,uintle,intle,uintne,intne,se,ue,sie,uie,float,floatbe,floatle,floatne,boolorfilename. If no initialiser is given then a zeroed bitstring oflengthbits is created.The initialiser for the
Bitsclass is precisely the same as forBitArray,BitStreamandConstBitStream.offsetis available when using thebytesorfilenameinitialisers. It gives a number of bits to ignore at the start of the bitstring.Specifying
lengthis mandatory when using the various integer initialisers. It must be large enough that a bitstring can contain the integer inlengthbits. It must also be specified for the float initialisers (the only valid values are 32 and 64). It is optional for thebytesandfilenameinitialisers and can be used to truncate data from the end of the input value.>>> s1 = Bits(hex='0x934') >>> s2 = Bits(oct='0o4464') >>> s3 = Bits(bin='0b001000110100') >>> s4 = Bits(int=-1740, length=12) >>> s5 = Bits(uint=2356, length=12) >>> s6 = Bits(bytes=b'\x93@', length=12) >>> s1 == s2 == s3 == s4 == s5 == s6 True
For information on the use of
autosee The auto initialiser.>>> s = Bits('uint:12=32, 0b110') >>> t = Bits('0o755, ue:12, int:3=-1')
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all(value[, pos])¶ Returns
Trueif all of the specified bits are all set to value, otherwise returnsFalse.If value is
Truethen1bits are checked for, otherwise0bits are checked for.pos should be an iterable of bit positions. Negative numbers are treated in the same way as slice indices and it will raise an
IndexErrorifpos < -s.lenorpos > s.len. It defaults to the whole bitstring.>>> s = Bits('int:15=-1') >>> s.all(True, [3, 4, 12, 13]) True >>> s.all(1) True
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any(value[, pos])¶ Returns
Trueif any of the specified bits are set to value, otherwise returnsFalse.If value is
Truethen1bits are checked for, otherwise0bits are checked for.pos should be an iterable of bit positions. Negative numbers are treated in the same way as slice indices and it will raise an
IndexErrorifpos < -s.lenorpos > s.len. It defaults to the whole bitstring.>>> s = Bits('0b11011100') >>> s.any(False, range(6)) True >>> s.any(1) True
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count(value)¶ Returns the number of bits set to value.
value can be
TrueorFalseor anything that can be cast to a bool, so you could equally use1or0.>>> s = BitString(1000000) >>> s.set(1, [4, 44, 444444]) >>> s.count(1) 3 >>> s.count(False) 999997
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cut(bits[, start, end, count])¶ Returns a generator for slices of the bitstring of length bits.
At most count items are returned and the range is given by the slice [start:end], which defaults to the whole bitstring.
>>> s = BitString('0x1234') >>> for nibble in s.cut(4): ... s.prepend(nibble) >>> print(s) 0x43211234
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endswith(bs[, start, end])¶ Returns
Trueif the bitstring ends with the sub-string bs, otherwise returnsFalse.A slice can be given using the start and end bit positions and defaults to the whole bitstring.
>>> s = Bits('0x35e22') >>> s.endswith('0b10, 0x22') True >>> s.endswith('0x22', start=13) False
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find(bs[, start, end, bytealigned])¶ Searches for bs in the current bitstring and sets
posto the start of bs and returns it in a tuple if found, otherwise it returns an empty tuple.The reason for returning the bit position in a tuple is so that it evaluates as True even if the bit position is zero. This allows constructs such as
if s.find('0xb3'):to work as expected.If bytealigned is
Truethen it will look for bs only at byte aligned positions (which is generally much faster than searching for it in every possible bit position). start and end give the search range and default to the whole bitstring.>>> s = Bits('0x0023122') >>> s.find('0b000100', bytealigned=True) (16,)
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findall(bs[, start, end, count, bytealigned])¶ Searches for all occurrences of bs (even overlapping ones) and returns a generator of their bit positions.
If bytealigned is
Truethen bs will only be looked for at byte aligned positions. start and end optionally define a search range and default to the whole bitstring.The count parameter limits the number of items that will be found - the default is to find all occurrences.
>>> s = Bits('0xab220101')*5 >>> list(s.findall('0x22', bytealigned=True)) [8, 40, 72, 104, 136]
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join(sequence)¶ Returns the concatenation of the bitstrings in the iterable sequence joined with
selfas a separator.>>> s = Bits().join(['0x0001ee', 'uint:24=13', '0b0111']) >>> print(s) 0x0001ee00000d7 >>> s = Bits('0b1').join(['0b0']*5) >>> print(s.bin) 010101010
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rfind(bs[, start, end, bytealigned])¶ Searches backwards for bs in the current bitstring and sets
posto the start of bs and returns it in a tuple if found, otherwise it returns an empty tuple.The reason for returning the bit position in a tuple is so that it evaluates as True even if the bit position is zero. This allows constructs such as
if s.rfind('0xb3'):to work as expected.If bytealigned is
Truethen it will look for bs only at byte aligned positions. start and end give the search range and default to0andlenrespectively.Note that as it’s a reverse search it will start at end and finish at start.
>>> s = Bits('0o031544') >>> s.rfind('0b100') (15,) >>> s.rfind('0b100', end=17) (12,)
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split(delimiter[, start, end, count, bytealigned])¶ Splits the bitstring into sections that start with delimiter. Returns a generator for bitstring objects.
The first item generated is always the bits before the first occurrence of delimiter (even if empty). A slice can be optionally specified with start and end, while count specifies the maximum number of items generated.
If bytealigned is
Truethen the delimiter will only be found if it starts at a byte aligned position.>>> s = Bits('0x42423') >>> [bs.bin for bs in s.split('0x4')] ['', '01000', '01001000', '0100011']
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startswith(bs[, start, end])¶ Returns
Trueif the bitstring starts with the sub-string bs, otherwise returnsFalse.A slice can be given using the start and end bit positions and defaults to the whole bitstring.
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tobytes()¶ Returns the bitstring as a
bytesobject (equivalent to astrin Python 2.7).The returned value will be padded at the end with between zero and seven
0bits to make it byte aligned.This method can also be used to output your bitstring to a file - just open a file in binary write mode and write the function’s output.
>>> s = Bits(bytes=b'hello') >>> s += '0b01' >>> s.tobytes() b'hello@'
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tofile(f)¶ Writes the bitstring to the file object f, which should have been opened in binary write mode.
The data written will be padded at the end with between zero and seven
0bits to make it byte aligned.>>> f = open('newfile', 'wb') >>> Bits('0x1234').tofile(f)
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unpack(fmt, **kwargs)¶ Interprets the whole bitstring according to the fmt string or iterable and returns a list of bitstring objects.
A dictionary or keyword arguments can also be provided. These will replace length identifiers in the format string.
fmt is an iterable or a string with comma separated tokens that describe how to interpret the next bits in the bitstring. See the entry for
readfor details.>>> s = Bits('int:4=-1, 0b1110') >>> i, b = s.unpack('int:4, bin')
If a token doesn’t supply a length (as with
binabove) then it will try to consume the rest of the bitstring. Only one such token is allowed.
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bin¶ Property for the representation of the bitstring as a binary string.
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bool¶ Property for representing the bitstring as a boolean (
TrueorFalse).If the bitstring is not a single bit then the getter will raise an
InterpretError.
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bytes¶ Property representing the underlying byte data that contains the bitstring.
When used as a getter the bitstring must be a whole number of byte long or a
InterpretErrorwill be raised.An alternative is to use the
tobytesmethod, which will pad with between zero and seven0bits to make it byte aligned if needed.>>> s = Bits('0x12345678') >>> s.bytes b'\x124Vx'
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hex¶ Property representing the hexadecimal value of the bitstring.
If the bitstring is not a multiple of four bits long then getting its hex value will raise an
InterpretError.>>> s = Bits(bin='1111 0000') >>> s.hex 'f0'
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int¶ Property for the signed two’s complement integer representation of the bitstring.
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intbe¶ Property for the byte-wise big-endian signed two’s complement integer representation of the bitstring.
Only valid for whole-byte bitstrings, in which case it is equal to
s.int, otherwise anInterpretErroris raised.
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intle¶ Property for the byte-wise little-endian signed two’s complement integer representation of the bitstring.
Only valid for whole-byte bitstring, in which case it is equal to
s[::-8].int, i.e. the integer representation of the byte-reversed bitstring.
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intne¶ Property for the byte-wise native-endian signed two’s complement integer representation of the bitstring.
Only valid for whole-byte bitstrings, and will equal either the big-endian or the little-endian integer representation depending on the platform being used.
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float¶
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floatbe¶ Property for the floating point representation of the bitstring.
The bitstring must be either 32 or 64 bits long to support the floating point interpretations, otherwise an
InterpretErrorwill be raised.If the underlying floating point methods on your machine are not IEEE 754 compliant then using the float interpretations is undefined (this is unlikely unless you’re on some very unusual hardware).
The
floatproperty is bit-wise big-endian, which as all floats must be whole-byte is exactly equivalent to the byte-wise big-endianfloatbe.
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floatle¶ Property for the byte-wise little-endian floating point representation of the bitstring.
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floatne¶ Property for the byte-wise native-endian floating point representation of the bitstring.
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len¶
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length¶ Read-only property that give the length of the bitstring in bits (
lenandlengthare equivalent).This is almost equivalent to using the
len()built-in function, except that for large bitstringslen()may fail with anOverflowError, whereas thelenproperty continues to work.
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oct¶ Property for the octal representation of the bitstring.
If the bitstring is not a multiple of three bits long then getting its octal value will raise a
InterpretError.>>> s = BitString('0b111101101') >>> s.oct '755' >>> s.oct = '01234567' >>> s.oct '01234567'
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se¶ Property for the signed exponential-Golomb code representation of the bitstring.
When used as a getter an
InterpretErrorwill be raised if the bitstring is not a single code.>>> s = BitString(se=-40) >>> s.bin 0000001010001 >>> s += '0b1' >>> s.se Error: BitString is not a single exponential-Golomb code.
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ue¶ Property for the unsigned exponential-Golomb code representation of the bitstring.
When used as a getter an
InterpretErrorwill be raised if the bitstring is not a single code.
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sie¶ Property for the signed interleaved exponential-Golomb code representation of the bitstring.
When used as a getter an
InterpretErrorwill be raised if the bitstring is not a single code.
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uie¶ Property for the unsigned interleaved exponential-Golomb code representation of the bitstring.
When used as a getter an
InterpretErrorwill be raised if the bitstring is not a single code.
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uint¶ Property for the unsigned base-2 integer representation of the bitstring.
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uintbe¶ Property for the byte-wise big-endian unsigned base-2 integer representation of the bitstring.
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uintle¶ Property for the byte-wise little-endian unsigned base-2 integer representation of the bitstring.
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uintne¶ Property for the byte-wise native-endian unsigned base-2 integer representation of the bitstring.
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__add__(bs)¶
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__radd__(bs)¶ s1 + s2Concatenate two bitstring objects and return the result. Either bitstring can be ‘auto’ initialised.
s = Bits(ue=132) + '0xff' s2 = '0b101' + s
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__and__(bs)¶
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__rand__(bs)¶ s1 & s2Returns the bit-wise AND between two bitstrings, which must have the same length otherwise a
ValueErroris raised.>>> print(Bits('0x33') & '0x0f') 0x03
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__bool__()¶ if s:Returns
Trueif at least one bit is set to 1, otherwise returnsFalse.This special method is used in Python 3 only; for Python 2.7 the equivalent is called
__nonzero__, but the details are exactly the same.>>> bool(Bits()) False >>> bool(Bits('0b0000010000')) True >>> bool(Bits('0b0000000000')) False
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__contains__(bs)¶ bs in sReturns
Trueif bs can be found in the bitstring, otherwise returnsFalse.Similar to using
find, except that you are only told if it is found, and not where it was found.>>> '0b11' in Bits('0x06') True >>> '0b111' in Bits('0x06') False
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__copy__()¶ s2 = copy.copy(s1)This allows the
copymodule to correctly copy bitstrings. Other equivalent methods are to initialise a new bitstring with the old one or to take a complete slice.>>> import copy >>> s = Bits('0o775') >>> s_copy1 = copy.copy(s) >>> s_copy2 = Bits(s) >>> s_copy3 = s[:] >>> s == s_copy1 == s_copy2 == s_copy3 True
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__eq__(bs)¶ s1 == s2Compares two bitstring objects for equality, returning
Trueif they have the same binary representation, otherwise returningFalse.>>> Bits('0o7777') == '0xfff' True >>> a = Bits(uint=13, length=8) >>> b = Bits(uint=13, length=10) >>> a == b False
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__getitem__(key)¶ s[start:end:step]Returns a slice of the bitstring.
The usual slice behaviour applies.
>>> s = Bits('0x0123456') >>> s[4:8] Bits('0x1') >>> s[1::8] # 1st, 9th, 17th and 25th bits Bits('0x3')
If a single element is asked for then either
TrueorFalsewill be returned.>>> s[0] False >>> s[-1] True
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__hash__()¶ hash(s)Returns an integer hash of the
Bits.This method is not available for the
BitArrayorBitStreamclasses, as only immutable objects should be hashed. You typically won’t need to call it directly, instead it is used for dictionary keys and in sets.
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__invert__()¶ ~sReturns the bitstring with every bit inverted, that is all zeros replaced with ones, and all ones replaced with zeros.
If the bitstring is empty then an
Errorwill be raised.>>> s = ConstBitStream(‘0b1110010’) >>> print(~s) 0b0001101 >>> print(~s & s) 0b0000000
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__len__()¶ len(s)Returns the length of the bitstring in bits if it is less than
sys.maxsize, otherwise raisesOverflowError.It’s recommended that you use the
lenproperty rather than thelenfunction because of the function’s behaviour for large bitstring objects, although calling the special function directly will always work.>>> s = Bits(filename='11GB.mkv') >>> s.len 93944160032 >>> len(s) OverflowError: long int too large to convert to int >>> s.__len__() 93944160032
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__lshift__(n)¶ s << nReturns the bitstring with its bits shifted n places to the left. The n right-most bits will become zeros.
>>> s = Bits('0xff') >>> s << 4 Bits('0xf0')
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__mul__(n)¶
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__rmul__(n)¶ s * n / n * sReturn bitstring consisting of n concatenations of another.
>>> a = Bits('0x34') >>> b = a*5 >>> print(b) 0x3434343434
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__ne__(bs)¶ s1 != s2Compares two bitstring objects for inequality, returning
Falseif they have the same binary representation, otherwise returningTrue.
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__or__(bs)¶
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__ror__(bs)¶ s1 | s2Returns the bit-wise OR between two bitstring, which must have the same length otherwise a
ValueErroris raised.>>> print(Bits('0x33') | '0x0f') 0x3f
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__repr__()¶ repr(s)A representation of the bitstring that could be used to create it (which will often not be the form used to create it).
If the result is too long then it will be truncated with
...and the length of the whole will be given.>>> Bits(‘0b11100011’) Bits(‘0xe3’)
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__rshift__(n)¶ s >> nReturns the bitstring with its bits shifted n places to the right. The n left-most bits will become zeros.
>>> s = Bits(‘0xff’) >>> s >> 4 Bits(‘0x0f’)
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__str__()¶ print(s)Used to print a representation of the bitstring, trying to be as brief as possible.
If the bitstring is a multiple of 4 bits long then hex will be used, otherwise either binary or a mix of hex and binary will be used. Very long strings will be truncated with
....>>> s = Bits('0b1')*7 >>> print(s) 0b1111111 >>> print(s + '0b1') 0xff
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__xor__(bs)¶
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__rxor__(bs)¶ s1 ^ s2Returns the bit-wise XOR between two bitstrings, which must have the same length otherwise a
ValueErroris raised.>>> print(Bits('0x33') ^ '0x0f') 0x3c
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